What is the ratio of P.E. w.r.t. ground and K.E. at the top most point – InterviewSolution

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1.	What is the ratio of P.E. w.r.t. ground and K.E. at the top most point of the projectile motion:-A. `cos^(2)theta`B. `sin^(2)theta`C. `tan^(2)theta`D. `cot^(2)theta`
Answer» Correct Answer - C `(K.E.)_("TOP")=(1)/(2)mu^(2)cos^(2)theta` vertical part of initial `K.E.=(P.E.)_("top")` `(P.E)_("TOP")=mgH=mg(u^(2)sin^(2)sin^(2)theta)/(2g)=(1)/(2)mu^(2) sin^(2)theta` `rArr((P.E.)_("TOP"))/((K.E.)_("TOP"))=`

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What is the ratio of P.E. w.r.t. ground and K.E. at the top most point of the projectile motion:-A. `cos^(2)theta`B. `sin^(2)theta`C. `tan^(2)theta`D. `cot^(2)theta`