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A ball is projected to attain the maximum range. If the height attained is H, the range isA. HB. 2HC. 4HD. H/2 |
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Answer» Correct Answer - C Maximum range for a given velocity is attained at `theta=45^(@)` `R_("max")=(u^(2)sin2theta)/(g)rArrR_("max")=(u^(2)sin90^(@))/(g)=(u^(2))/(g)` `therefore R_("max")=4.H_("max")` |
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