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A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is `k`. If radius of the ball be `R`, then the fraction of total energy associated with its rotation will be.A. `(K^2+R^2)/R^2`B. `K^2/R^2`C. `K^2/(K^2+R^2)`D. `R^2/(K^2+R^2)` |
Answer» Correct Answer - C T.K.E.=`1/2mv^2(1+K^2//R^2)` R.K.E.=`1/2mv^2(K^2//R^2)` |
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