A ball weighing 1 kg is moving horizontally at 12 ms^(-1). It collides head on with another of double the mass moving in oppssite direction with double the speed. If the coefficient of restitution is 2/3, the energy lost in the collision is given by :

A ball weighing 1 kg is moving horizontally at 12 ms^(-1). It collide

1.	A ball weighing 1 kg is moving horizontally at 12 ms^(-1). It collides head on with another of double the mass moving in oppssite direction with double the speed. If the coefficient of restitution is 2/3, the energy lost in the collision is given by :
Answer» 60 J 120 J 240 J 480 J Solution :According to conservation of momnetum, `1xx12+2xx(-24)=1xxv_(1)+2xxv_(2)`. ` impliesv_(1)+2v_(2)=36` …..(i) ALSO `E=(v_(2)-v_(1))/(u_(1)-u_(2))implies 2/3=(v_(2)-v_(1))/(12-(-24))` `implies v_(2)-v_(1)=24` Adding (i)&(ii), `3v_(2)=60 impliesv_(1)=20 m//s`. LOSS of energy=`1/2xx1xx12^(2)+1/2xx2(-34)` `-(1/2xx1xx(-4)^(2)+1/2xx2xx(20)^(2))` =72+576-(8+400) =240 J.

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A ball weighing 1 kg is moving horizontally at 12 ms^(-1). It collides head on with another of double the mass moving in oppssite direction with double the speed. If the coefficient of restitution is 2/3, the energy lost in the collision is given by :

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