1.

A ball weighing 150g is moving with an initial velocityoverline(u)=(3overset(wedge)(i)+4overset(wedge)(j))ms^(-1) After being hit by the player its final velocity is overline(u)=(3overset(wedge)(i)+4overset(wedge)(j))ms^(-1)What is the magnitude of change in momentam in kg ms^(-1)

Answer»

`1kg ms^(-1)`
`2kg ms^(-1)`
`1.5kg ms^(-1)`
`2.5kg ms^(-1)`

SOLUTION :Here change in momentum
`= -2 mu`
`-2xx(150)/(10000)[3hati+4hatj]`
`=(3000)/(1000)[-3hati-4hatj]`
`=-[(9)/(1)hati-(6)/(5)hatj]`
Magnitude `Ipl =sqrt((81)/(100)+(36)/(25))=(15)/(10)`
`1.5 kg m^(-1)S`Hence (C) is the right choice.


Discussion

No Comment Found

Related InterviewSolutions