1.

A ballet dancer is rotating at angular velocity `omega` on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by `1//4^(th)` of his initial radius of gyration, his final angular velocity isA. `(3 omega)/4`B. `(9 omega)/4`C. `(9 omega)/16`D. `(16 omega)/9`

Answer» Correct Answer - D
`I_(1)omega_(1)=I_(2)omega_(2),mk_(1)^(2)omega_(1)=mk_(2)^(2)omega_(2),k_(1)^(2)omega_(1)=(3/4k_(1))^(2)omega_(2)`


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