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The uniform `120 N` board shown in figure is supported by two ropes. A `400 N` weight is suspended one-fourth of the way from the left end. Choose the correct options A. `T_(1)=185N`B. `T_(2)=371N`C. `T_(2)=185N`D. `tan theta=0.257` |
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Answer» Correct Answer - A::B::D Taking moments about the left edge and resolving `T_(1)` into `x` and `y` components, `sum tau=0` yields `LT_(1) cos 30^(@)-(0.25 L)(400)` `-(0.5 L)(120)=0` Dividing throught by `L` and solving, we get `T_(1)=185 N` Substituting into our earlier equations, we get `T_(1)=185 N` `T_(2) = sin theta=92.5 N` and `T_(2)=cos theta=360 N` Dividing the equations yields `tan theta=0.257, `or `theta=14.4^(@)` Than `0.249 T_(2)=92.5` and `T_(2)=371 N` One can always chek moment problem results by taking moments about another point, such as the right end of the bar for this problem |
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