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The moment of inertia of ring about an axis passing through its diameter is `I`. Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane isA. `2I`B. `I`C. `I//2`D. `I//4` |
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Answer» Correct Answer - A `I=(MR^(2))/2` and `I^(1)=MR^(2)=2I` |
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