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A balloon is going vertically upward with a velocity of 15 ms^-1. When it is at a height of 50 m above the ground a stone is gently dropped from it. The stone will reach the ground in time (take g = 10 ms^-2): |
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Answer» 5 s `:.` Take U as -ve.50=-`15xxt+(1)/(2)10.t^(2)` `implies 5t^(2)-15t-50=0` `implies5t^(2)-15t-50=0` `implies t^(2)-3t-10=0` `implies t=5 s` |
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