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A bar magnet `A` of magnetic moment `M_(A)` is found to oscillate at a frequency twice that of magnet `B` of magnetic moment `M_(B)` when placed in a vibrating magneto-meter. We may say thatA. `M_=2M_(B)`B. `M_(A)=8M_B`C. `M_(A)=4M_(B)`D. `M_(B)=8M_(A)` |
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Answer» Correct Answer - C `v=1/(2pi)sqrt((MB_(H))/I)implies v prop sqrt(M)` `implies v_(A)/V_(B)=sqrt(M_(A)/M_(B)) implies2/1=sqrt(M_(A)/M_(B))implies M_(A)=4M_(B)` |
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