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The time period of oscillation of a freely suspended bar magnet with usual notations is given byA. `T=2pisqrt(I/(MB_(H)))`B. `T=2pisqrt((MB_(H))/I)`C. `T=sqrt(I/(MB_(H)))`D. `T=2pisqrt(B_(H)/(MI))` |
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Answer» Correct Answer - A Theory based |
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