A bar magnet has a magnetic moment of 200 A m? The magnet is suspended in a magnetic field of 0.30 `"N A"^(-1)" m"^(-1)`. The torque required to rotate the magnet from its equilibrium position through an angle of `30^(@)`, will beA. 30 N mB. `30sqrt(30)` N mC. 60 N mD. `60sqrt(3)` N m

A bar magnet has a magnetic moment of 200 A m? The magnet is suspended

1.	A bar magnet has a magnetic moment of 200 A m? The magnet is suspended in a magnetic field of 0.30 `"N A"^(-1)" m"^(-1)`. The torque required to rotate the magnet from its equilibrium position through an angle of `30^(@)`, will beA. 30 N mB. `30sqrt(30)` N mC. 60 N mD. `60sqrt(3)` N m
Answer» Correct Answer - A Torque experienced by a magnet suspended in a uniform magnetic field `B` is given by `tau=MBsintheta` Here, `M=200"A m"^(2)`, B= 0.30 N `A^(-1) m^(-1)` and `theta= 30^(@)` `thereforetau=200xx0.30xxsin30^(@)` `tau=30"N m"`

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A bar magnet has a magnetic moment of 200 A m? The magnet is suspended in a magnetic field of 0.30 `"N A"^(-1)" m"^(-1)`. The torque required to rotate the magnet from its equilibrium position through an angle of `30^(@)`, will beA. 30 N mB. `30sqrt(30)` N mC. 60 N mD. `60sqrt(3)` N m

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