1.

A bar magnet is 10 cmlonggiven the horizontalcomponent of earth field to be 0.4 gauss the polestrengthof the magnetis

Answer»

9A-m
6.75 A-m
27 A-m
1.35 A-m

Solution :Lengthof magnet =`10 cm =10xx10^(-2)m`
`r=15xx10^(-2)m`
`OP=sqrt(225-25)=sqrt(200)cm`
SINCE at the neutral point magnetic field due to the magnet equal to `B_(H`

`B_(H)=(mu_(0))/(4pi).(M)/(OP^(2)+AO^(2))^(3//2)`
`(0.4xx10^(-4))/(10^(-7))xx225xx10^(-4^(3//2))=M`
`0.4xx10^(3)xx10^(-6)=M`
`M=1.35 A-m`


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