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A bar magnet is kept in the earth's magnetic field with its north pole pointingearth's north. The distance between the null point is 20 cm. If earth's horizontal magnetic field is4 xx 10^(-5)T, then find the magnetic moment of the magnet. |
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Answer» Solution :The null points are formed on the equatorial line. At null point the RESULTANT field is zero . `:. B_(e) = (mu_0)/( 4pi) (M)/(d^(3))` ` = > 4 xx 10^(-5) = (4 pi xx 10^(-7))/(4pi) xx (M)/(10^(-3))` `IMPLIES M = (4 xx 10^(-5) xx 10^(-3))/(10^(-7)) = 0.4 Am^(2)` |
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