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A bar magnet made of steel has magnetic moment 2.5 A∙m2 and mass 6.6 × 10-3 kg. Given that the density of steel is 7.9 × 103 kg/m3, find the intensity of magnetization of the magnet. |
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Answer» Data : M = 2.5 A∙m2, m = 6.6 × 10-3 kg, ρ = 7.9 × 103 kg/m3 Volume, V = \(\cfrac{m}\rho\) The intensity of magnetization of the magnet is Mz = M ∙ \(\cfrac{\rho}m\) = 2.5 x \(\cfrac{M}V\) = 2.992 × 106 A/m [Note : Intensity of magnetization = magnetization.] |
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