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InterviewSolution
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An electron in an atom revolves around the nucleus in an orbit of radius 0.5 Å. Calculate the equivalent magnetic moment if the frequency of revolution of the electron is 10 MHz. |
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Answer» Data : r = 0.5 Å = 5 × 10-11 m, f = 1010 MHz = 1016 Hz, e = 1.6 × 10-19 C Equivalent current, I = \(\cfrac eT\) = ef The equivalent magnetic moment is M = IA = ef(πr2) = (1.6 × 10-19)(1016)(3.142)(5 × 10-11)2 = 1.6 × 3.142 × 25 × 10-25 = 1.257 × 10-23 A∙m2 |
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