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A bar magnet makes 40 oscillations per minute in a vibration magnetometer. An identical magnet is demagnetised completely and is placed over the magnet in the magnetometer. Calculate the time taken for 40 oscillations by this combination. Ignore induced magnetism. |
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Answer» Solution :In the first case frequency of oscillaton , ` v =(1)/(2PI) SQRT((MB)/(I))` In the second case frequency of oscillation , `v^(1) = (1)/(2pi) sqrt((MB)/(2I) ) implies (v^(1))/(v) = (1)/(sqrt(2)) , (T^(1))/(T) = sqrt(2) (or) T^(1) = sqrt(2)T` `(or) 40T^(1) = sqrt(2) xx 40T` `(or) t^(1) = sqrt(2)t = sqrt(2)"MINUTE" = 1.414` minute |
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