InterviewSolution
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InterviewSolution
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A bar magnet of length 0.1 m and with a magnetic moment of `5Am^(2)` is placed in a uniform a magnetic field of intensity 0.4T, with its axis making an angle of `60^(@)` with the field. What is the torque on the magnet ? |
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Answer» Given, `2l = 0.1 m, m = 5A - m^(2), B = 0.4T, theta = 60^(@)`. Torque, `T = mB sin theta = 5 xx 0.4 xx sin 60^(@) = 2 xx (sqrt(3))/(2)` `:. T = 1.732 N - m` |
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