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A bar magnet of length 0.1 m has pole strength of 50Am. Calculate the magentic field at a distance of 0.2 m from its centre on its equatorial line. |
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Answer» Solution :Length of the MAGNET `,2l=0.1 m or l = 0.05 m` Distanceof the point on EQUATORIAL line , d = 0.2 m Pole strength , m = 50Am Magnetic induction on the equatorial line of a bar magnet is , ` B = (mu_0)/(4pi) ( m)/((d^(2) + l^(2))^(3//2))=(mu_0)/(4pi)(m(2l))/((d^(2) + l^(2))^(3//2))` `B=(4pi xx 10^(-7))/(4pi) xx (50 xx 0.1)/([(0.2)^(2) + (0.05)^(2)]^(3//2))` `=5.7 xx 10^(-5)T` |
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