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A bar magnet of length 10 cm and pole strength 2 Am is making an angle 60^(@) with a uniform field of induction 50T. Find the couple acting on it. |
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Answer» Solution :Length of the bar magnet , 2l=10cm = 0.1 m pole strength , m =2Am magnetic induction , B=50T Angle between the magnetic FILED and axis of the magnet ,` theta =60^(@)` `:.`Couple ACTING on the bar magnet,` tau = MB sin theta ` `implies tau = (2 l xx m)B sin theta = ( 0.1 xx 2 ) 50 sin 60^(@)` `= 0.2 xx 50 xx (sqrt(3))/(2) = 6.66 N-m` |
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