A bar magnet of magnetic dipole moment `10 Am^(2)` is in stable equilibrium . If it is rotated through `30^(@)` , find its potential energy in new position [Given , B = 0.2 T]

A bar magnet of magnetic dipole moment `10 Am^(2)` is in stable equili

1.	A bar magnet of magnetic dipole moment `10 Am^(2)` is in stable equilibrium . If it is rotated through `30^(@)` , find its potential energy in new position [Given , B = 0.2 T]
Answer» `M = 10 A m^(2)` B = 0.2 T U = `- MB cos theta` = `-10 xx 0.2 xx (sqrt3)/(2)` `= - sqrt3 J`

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A bar magnet of magnetic dipole moment `10 Am^(2)` is in stable equilibrium . If it is rotated through `30^(@)` , find its potential energy in new position [Given , B = 0.2 T]

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