1.

A bar of iron is 10 cm at `20^(@)C`. At `19^(@)C` it will be `(alpha_(Fe)=11xx10^(-6)//.^(@)C)`A. `11xx10^(-6)`cm longerB. `11xx10^(-6)cm` cm shorterC. `11xx10^(-5)cm` shorterD. `11xx10^(-5)cm` longer

Answer» Correct Answer - C


Discussion

No Comment Found

Related InterviewSolutions