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A barometer has liquid-1 with density 1 Kg/m^3 and height 10 cm below the outside level above that a liquid-2, if the gauge pressure of gas is 0.5 Pa, what is the pressure liquid-2?(a) 0.5 Pa(b) 1 Pa(c) 1.5 Pa(d) 2 PaThe question was asked in unit test.My doubt is from Differential Pressure Measurements in division Temperature and Pressure of Basic Chemical Engineering

Answer»

The CORRECT ANSWER is (a) 0.5 Pa

The explanation is: GAUGE pressure of GAS + Pressure of liquid-2 = Pressure of liquid-1, => Pressure of liquid-2 = 1*10*0.1 – 0.5 = 0.5 Pa.



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