1.

A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is A. 8.6 B. 6.4 C. 10.6 D. 7.6

Answer»

Mean \((X)\)\(\frac{38+70+48+34+42+55+63+46+54+44}{10}\) 

\((\bar X)\) = \(\frac{494}{10}\) 

Xid = (xi - Mean)
38-11.4
7020.6
48-1.4
34-15.4
42-7.4
555.6
6313.6
46-3.4
544.6
44-5.4
\(\Sigma d_i\) = 0

Here, N= 10, Σd = 0

Mean deviation = \(\Big(\frac{\Sigma d_i}{N}\Big)\) 

M.D. = \(\Big(\frac{0}{10}\Big)\) 

Hence, MD is 0



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