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A battery of emf 1.4 volt and internal resistance 2Omega is connected to a resistor is of 100Omega through an ammeter. The resistance of the ammter is (4)/(3)Omega. A voltmeter has also been connected to measure the potentialdifference across the resistor 100Omega. If the ammeter reads 0.02A and voltmeter reading is 1.10 volt then error in the reading of voltmeter is x volt then find value ofx((100)/(25)) in nearest integer. |
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Answer» `x=(42)/(31)-1.1=1.35-1.1=0.25` `x((100)/(25))=1`
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