1.

A battery of emf 10 V and internal resistance 3Omega is connected to a resistor. The current in the circuit is 0.5A. The terminal voltage of the battery when the circuit is closed is

Answer»

10 V
ZERO
8.5 V
1.5 V

SOLUTION :`V=xi-Ir=10-(0.5xx3)=8.5V`


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