1.

A battery of emf 10 V internal resistance 3 Omega is connected to a resistor R. (i) If the current in the circuit is 0.5 A. calculate the value of R. (ii) What is the terminal voltage of the battery when the cirucit is closed.

Answer»

SOLUTION :`I=(E)/(R+r)or`
`R=(E)/(I)-r-(10)/(0.5)-3=17Omega`
`V=IR=0.5xx17=8.5V`.


Discussion

No Comment Found

Related InterviewSolutions