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A battery of emf 12 V and internal resistance 2 Omega is connected to a 4 Omega resistor as shown in the Fig. Show that a voltmeter when placed across the cell and across the resistor, in turn, gives the same reading. |
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Answer» SOLUTION :Here emf of battery `EPSI` =12 V, internal resistance R=2 `Omega` and EXTERNAL resistance R=4`Omega` CIRCUIT current `I = (epsi)/(r + R) = (12)/(2 + 4) = 2A` ` therefore ` Voltmeter reading when placed across the cell `V_1 = epsi - Ir = 12 - 2 xx 2 = 8V` and voltmeter reading when connected across the resistor `V_2 = IR = 2 xx 4 = 8V` Obviously `V_1 = V_2 = 8V` |
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