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A battery of emf 6V internal resistance 5`Omega` is joined in parallel with another cell of emf of 10V and internal resistance `1Omega` and the combination is used to send current through a resistor of `12Omega`. Calculate the current through each battery. |
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Answer» Correct Answer - `6/11 A through 6-V battery in opposition to its emf and `(1)3/11` A through 10-V battery in direction of the emf |
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