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A battery of internal resistance 3Omega is connected to 20Omega resistor and the potential difference across the resistor is 10V. If another resistor 30Omega is connected in series with the first resistor and battery is again connectecl to the combination, then calculate the e.m.f and terminal potential difference across the combination.. |
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Answer» SOLUTION :Case-I `I = ( EPSI )/( R +r) or V = ( epsi R)/( R+ r)` `epsi = 11.5 V` Case-II `I = ( epsi)/( R _(s ) + r ) or V =(epsi R _(S))/( R + r )` `R _(S) = 20 + 30 = 50 Omega` Substitution and OBTAINING `V = 10.849V` |
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