1.

A batteryof emf 10 v and internal resistane 3 Omega is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistane of the resistors ? What is the terminal voltage of the battery when the circuit is closed ?

Answer»

SOLUTION :`E= I (R+r ) `
` 10= 0.5 ( R+ 3 ) `
` R= 17 Omega `
`V =E - IR = 10-0.5 xx 3= 8.5 V `


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