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A batteryof emf 10 v and internal resistane 3 Omega is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistane of the resistors ? What is the terminal voltage of the battery when the circuit is closed ? |
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Answer» SOLUTION :`E= I (R+r ) ` ` 10= 0.5 ( R+ 3 ) ` ` R= 17 Omega ` `V =E - IR = 10-0.5 xx 3= 8.5 V ` |
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