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A bead of mass m is located on a parabolic wire with its axis vertical and vertex at the origin as shown in figure and whose equastion is `x^(2) =4ay`. The wire frame is fixed and the bead is released from the point `y=4a` on the wire frame from rest. The tangential acceleration of the bead when it reaches the position given by `y=a` is A. `g/2`B. `(sqrt3g)/(2)`C. `(g)/(sqrt2)`D. g |
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Answer» Correct Answer - C `x^(2)=4ay,(dy)/(dx)=1/(2a)x` at point `(2a,2a),(dy)/(dx)=1,theta=45^(@)` Component of weight along tangential direction is `mg sin theta` Tangential acceleration is `g sin theta` |
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