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A beam of light consisting of two wavelength 800 nm and 600 nm is used to obtain the interference fringes in YDSE on a screen held 1.4 m away. If the two slits are separated by 0.28 mm, calculate the least distance from thecentral bright maximum, where the bright fringes of the two waveength coincide. |
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Answer» Solution :`x=N lamda_1D/d=(n+1)lamda_2 D/d` `n times 800=(n+1) lamda_2 D/d` `n=3` `x=nlamda_1 D/d=3 times 800 times (10^-9 times 1.4)/(0.28 times 10^-3)=12 mm` |
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