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A beam of light consisting of two wavelengths 800nm and 600nm is used to obtain the interference fringes in a Young's double slit experiment on a screen placed 1.4m away. If the two slits are separated by 0.28mm, calculate the least distance from the central bright maximum where the bright fringes of the two wavelengths coincide. |
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Answer» Solution :The two bright fringes will coincide when `mlambda_(1)=(m+1)lambda_(2)` `mxx800xx10^(-9)=(m+1)xx600xx10^(-9)` `:.m=3` `X_(m)=(mDlambda_(1))/(d)` `=((3xx1.4xx800xx10^(-9)))/((0.28xx10^(-3)))m` `=12XX10^(-3)m` |
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