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A beam of light converges at a point P. A concave lens of focal length 16 cm is placed in the path of this beam 12 cm from P. Draw a ray diagram and find the location of the point at which the beam would now converge. |
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Answer» Solution :As shown in Fig. 9.42, the beam of light now converges at point Q INSTEAD of point P. question for concave lens `u = CP = + 12 cm` and `f= - 16 cm`. Hence, from lens FORMULA `1/v - 1/u = 1/f` We have: `1/v -1/(+12) = 1/(-16)` `rArr 1/v =1/12 -1/16 = 1/48` or `v= +48` cm 
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