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A beam of light of lambda= 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between first dark fringes on either side of the central bright fringe is ... |
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Answer» `1.2` cm `d sin thea_(1)= lambda` `:. sin theta_(1)=(lambda)/(d)` but `sin theta_(1)=(x_(1))/(D)` `:. (x_(1))/(D)=(lambda)/(d)` `:.x_(1)=(lambdaD)/(d)` `:.` The distance between first minimum from central maximum on both the SIDES `=2x_(1)` `:.2x_(1)=(2lambdaD)/(d)` `=(2xx600xx10^(-9)xx2)/(1xx10^(-3))` `=2400xx10^(-6)m=2.4 mm` |
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