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A beam of relativistic particles with kinetic energy T strikes against an absorbing target. The beam current equals I, the charge and rest mass of each particle are equal to e and m_0 respectively. Find the pressure developed by the beam on the target surface, and the power liberated there. |
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Answer» Solution :Let the total force exerted by the BEAM on the target surface be F and the power liberated there be P. Then, using the result of the PREVIOUS problem we SEE `F=Np=N/csqrt(T(T+2m_0c^2))=(I)/(ec)sqrt(T(T+2m_0c^2))` since `I=Ne`, N being the number of particles striking the target per SECOND. Also, `P=N((m_0c^2)/(sqrt(1-v^2//c^2))-m_0c^2)=I/eT` These will be, respectively, equal to the pressure and power developed per unit area of the target if I is current DENSITY. |
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