A berillium particle (z = 4) having 5.3 MeV energy experience head-on collision with gold atom (z = 79). It can move to what closest distance to gold nucleus ?

A berillium particle (z = 4) having 5.3 MeV energy experience head-on

1.	A berillium particle (z = 4) having 5.3 MeV energy experience head-on collision with gold atom (z = 79). It can move to what closest distance to gold nucleus ?
Answer» `10.32xx10^(-14)m` `8.58xx10^(-14)m` `3.56xx10^(-14)m` `1.25xx10^(-14)m` Solution :`8.58xx10^(-14)m` Minimum DISTANCE, `r_(0)=(KXX(79e)(4e))/(K)` `=(9xx10^(9)xx79xx4xx(1.6xx10^(-19))^(2))/(5.3xx10^(6)xx1.6xx10^(-19))` `=858.56xx10^(-16)` `~~8.58xx10^(-14)m`

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A berillium particle (z = 4) having 5.3 MeV energy experience head-on collision with gold atom (z = 79). It can move to what closest distance to gold nucleus ?

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