A bias dice has probability of getting any of the odd number equal to

1.	A bias dice has probability of getting any of the odd number equal to the inverse of immediate greater even number and the possibility of getting any of the even number are equal, then what is the probability of getting an even number.1. \(1\over 36\)2. \(1\over 18\)3. \(1\over 12\)4. \(1\over9\)
Answer» Correct Answer - Option 3 : \(1\over 12\) Concept: General Rule: The number of ways for selecting r from a group of n (n > r) = nCr The probability of particular case = \(\rm \text{Number of ways for the case can be executed}\over{\text{Total number of ways for selection}}\) The sum of the possible case probabilities = 1 Calculation: According to the question; Probability of getting '1' = \(1\over2\) Probability of getting '3' = \(1\over4\) Probability of getting '5' = \(1\over6\) Let the probability of getting an even number be x As ∑ P = 1 ⇒ x + \(1\over2\) + \(1\over4\) + \(1\over6\) = 1 ⇒ x = \(\boldsymbol{1\over12}\)

A bias dice has probability of getting any of the odd number equal to the inverse of immediate greater even number and the possibility of getting any of the even number are equal, then what is the probability of getting an even number.1. \(1\over 36\)2. \(1\over 18\)3. \(1\over 12\)4. \(1\over9\)

Answer» Correct Answer - Option 3 : \(1\over 12\)

Concept:

General Rule:

The number of ways for selecting r from a group of n (n > r) = nCr
The probability of particular case = \(\rm \text{Number of ways for the case can be executed}\over{\text{Total number of ways for selection}}\)
The sum of the possible case probabilities = 1

Calculation:

According to the question;

Probability of getting '1' = \(1\over2\)

Probability of getting '3' = \(1\over4\)

Probability of getting '5' = \(1\over6\)

Let the probability of getting an even number be x

As ∑ P = 1

⇒ x + \(1\over2\) + \(1\over4\) + \(1\over6\) = 1

⇒ x = \(\boldsymbol{1\over12}\)

Discussion

No Comment Found

Related InterviewSolutions

The chance of a student passing an exam is 30% , the chance of a student passing the exam and getting above 80% marks in it is 10%, if it is given that a student has passed the examination, then find the probability that the student has secure more than 80% marks in the exam ?1. 3/82. 1/33. 1/94. 1/8
A bag contains 5 black and 6 white balls; one balls are drawn at random. What is the probability that the balls drawn are black?1. 6/112. 5/63. 5/114. 2/5
Person A can hit a target 4 times in 5 attempts. Person B - 3 times in four attempts. Person C - 2 times in 3 attempts. They fire a volley. The probability that the target is hit atleast two times is1. 3/42. 1/23. 5/64. 1
A dice is thrown, find the probability of getting a number which is exactly divisible by 2.1. 2/32. 1/23. 1/34. 1/4
If two dice are thrown simultaneously then find the probability that the sum of the numbers coming up on them is 11, given that the number 5 always occurs on the first dice.1. 1/32. 1/363. 1/124. 1/6
Let A and B be two events such that \(\rm P\left( \overline{A\cup B} \right)=\frac{1}{6}\), \(\rm P\left( A\cap B \right)=\frac{1}{4}\) and \(\rm P\left( \overline{A} \right)=\frac{1}{4}\), where A̅ is the complementary event of A. Then A and B are:1. Equally likely but not independent.2. Equally likely and mutually exclusive.3. Mutually exclusive and independent.4. Independent but not equally likely.
A bag has 10 red balls, 5 green balls and ‘x’ yellow balls. If the probability of drawing 2 red balls from the bag is 13/57 more than the probability of drawing 2 yellow balls then find total balls in the bag?1. 152. 253. 204. 195. 30
1/5th of cistern can be emptied in 2 hours. Calculate what percentage of tank was filled if it takes 6 hours to empty that amount of tank1. 25% 2. 60%3. 50%4. 40%5. 45%
Two fair dice are rolled. What is the probability that the total score is a prime number?1. \(\dfrac{1}{6}\)2. \(\dfrac{5}{12}\)3. \(\dfrac{1}{2}\)4. \(\dfrac{7}{9}\)
A random variable X has the distribution law as given below:X123P(X = x)0.30.40.3The variance of the distribution is:1. 0.42. 0.63. 0.24. None of these

A bias dice has probability of getting any of the odd number equal to the inverse of immediate greater even number and the possibility of getting any of the even number are equal, then what is the probability of getting an even number.1. \(1\over 36\)2. \(1\over 18\)3. \(1\over 12\)4. \(1\over9\)

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment