1/5th of cistern can be emptied in 2 hours. Calculate what percentag

1.	1/5th of cistern can be emptied in 2 hours. Calculate what percentage of tank was filled if it takes 6 hours to empty that amount of tank1. 25% 2. 60%3. 50%4. 40%5. 45%
Answer» Correct Answer - Option 2 : 60% Given: 1/5^th of cistern emptied = 2 hours Calculation: 1/5^th of cistern is emptied in 2 hours ⇒ Time taken to empty the whole cistern = 2 × (5/1) ⇒ Time taken to empty the whole cistern = 10 hours Now, Within 6 hours cistern was emptied ⇒ 10 hours to empty whole cistern = T1 ⇒ 6 hours to empty particular portion of cistern = T2 ⇒ Proportion of cistern = T2/T1 ⇒ Proportion of cistern = 6/10 ⇒ Proportion of cistern = 3/5 ⇒ Percentage of cistern filled = 3/5 × 100 ∴ Cistern was filled up to 60% of capacity

1/5th of cistern can be emptied in 2 hours. Calculate what percentage of tank was filled if it takes 6 hours to empty that amount of tank1. 25% 2. 60%3. 50%4. 40%5. 45%

Answer» Correct Answer - Option 2 : 60%

Given:

1/5^th of cistern emptied = 2 hours

Calculation:

1/5^th of cistern is emptied in 2 hours

⇒ Time taken to empty the whole cistern = 2 × (5/1)

⇒ Time taken to empty the whole cistern = 10 hours

Now, Within 6 hours cistern was emptied

⇒ 10 hours to empty whole cistern = T1

⇒ 6 hours to empty particular portion of cistern = T2

⇒ Proportion of cistern = T2/T1

⇒ Proportion of cistern = 6/10

⇒ Proportion of cistern = 3/5

⇒ Percentage of cistern filled = 3/5 × 100

∴ Cistern was filled up to 60% of capacity

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