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A biconvex lens of focal length 15 cm is in front of a plane mirror. The distance between the lens and the mirror is 10 cm. A small object is kept at a distance of 30 cm from the lens. The final image is |
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Answer» virtual and at a distance of 16 cm from the mirror {(1/v) + (1/30) }= 1/15 rArr v = 30 cm` so, object for place mirror is 20 cm from it towards right. `rArr`Image formed = 20 cm left from plane mirror. This behaves as virtual object for lens at a distance of 10 cm left.  using lens formula, (1/v.) + (1/u) = 1/f `rArr (1//v.) + (1//-10) = 1//15 rArr v. = 6 cm` So, image formed is real and at a distance 16 cm from mirror. `mu = A + (B)/(lambda^(2)) + (C )/(lambda^(4)) + ...` `f_(R) ge f_(v)`. |
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