1.

A bivalent metal as an equivalent mass of 32. The molecular mas of the metal nitrate is

Answer»

168
192
188
182

Solution :GIVEN equivalent MASS of BIVALENT metal,
`M^(2+)=32`
`:.` atomic mass of `M=32xx2=64`
The metal nitrate FORMED has the formula `M(NO_(3))_(2)`
`:.` moleclar mass of themetal nitrate
`=64+28=96=188`


Discussion

No Comment Found