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A black body at high temperature `T` `K` radiates energy at the rate of `E W//m^(2)`. When the temperature falls to `(T//2) K`, the radiated energy will beA. E/16B. E/4C. E/2D. 16 E |
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Answer» Correct Answer - A `(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)=(((T)/(2))/(T))^(4)=(1)/(16)` `therefore E_(2)=(E)/(16)`. |
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