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A black body at high temperature TK radiates energy at the rate "EW/ m"^(2). When the temperature falls to ((T)/(2)) K, the radiated energy will be : |
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Answer» SOLUTION :`(E_(2))/(E_(1))=((T_(2))/(T_(1)))^(4)""rArr(E_(2))/(E_(1))=((T//2)/(T))^(2)` `rArrE_(2)=(E)/(16)` Thus correct CHOICE is (d). |
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