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A blackened platinum wire is of length 0.1 m and circumference 2 xx 10^(-4) m. calculate the rate at which the wire is loosing energy if it's temperature is 3000 K . |
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Answer» SOLUTION :Rate of loss energy = `E sigma T^4 XX A` Here e = 1 (blackened surface), `sigma = 5.67 xx 10^(-8) J m^(-2) s^(-1) k^(-4)` T= 3000K A = `(2 pi r) xx l = 2 pi (2 xx 10^(-4) ) xx 0.1 m^2`. |
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