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A blackened platinum wire is of length 0.1 m and circumference 2 xx 10^(-4) m. calculate the rate at which the wire is loosing energy if it's temperature is 3000 K . |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Rate of loss energy = `<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> sigma T^4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> A` <br/> Here e = 1 (blackened surface), <br/> `sigma = 5.67 xx 10^(-8) <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a> m^(-2) s^(-1) k^(-4)` <br/> T= <a href="https://interviewquestions.tuteehub.com/tag/3000k-1852552" style="font-weight:bold;" target="_blank" title="Click to know more about 3000K">3000K</a> <br/> A = `(2 pi r) xx l = 2 pi (2 xx 10^(-4) ) xx 0.1 m^2`.</body></html> | |