A block A of mass m connected with a spring of force constant k is executing SHM.The displacement time equation of the block is x=`x_(0) = a sinomegat`. An indentical block B moving towards negative x -axis with velocity `v_(0)` collides elastically with block A at time t=0. Then A. displacement time equation of A after collision will be `x=x_(0) - v_(0)sqrt(m/k)sinomegat`B. displacement time equation of A after collision will be `x=x_(0)+v_(0)sqrt(m/k)sinomegat`C. Velocity of b just after collision will be a `omega` towards positive x-direction.D. velocity of B just after collision will be `v_(0)` towards positive x-direction.

A block A of mass m connected with a spring of force constant k is exe

1.	A block A of mass m connected with a spring of force constant k is executing SHM.The displacement time equation of the block is x=`x_(0) = a sinomegat`. An indentical block B moving towards negative x -axis with velocity `v_(0)` collides elastically with block A at time t=0. Then A. displacement time equation of A after collision will be `x=x_(0) - v_(0)sqrt(m/k)sinomegat`B. displacement time equation of A after collision will be `x=x_(0)+v_(0)sqrt(m/k)sinomegat`C. Velocity of b just after collision will be a `omega` towards positive x-direction.D. velocity of B just after collision will be `v_(0)` towards positive x-direction.
Answer» Correct Answer - A::C::D

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