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| 1. |
A block is pushed across a floor by a constant force that is applied at downward angle theta (Fig. 6-33). Figure 6-53 gives the acceleration magnitude a versus a range of values for the coefficient of kinetic friction mu_(k) between block and floor: a_(1) = 3.0 m//s^(2) mu_(2) = 0.20, and mu_(k3) = 0.40. What is the value of theta ? |
| Answer» SOLUTION :`theta=60^(@)` | |