A block mass 3 kg slides down a frictionless inclined plane of length 6 m and height 4 m. if the block is released from rest at the top of the incline, what is its speed at the bottom?

A block mass 3 kg slides down a frictionless inclined plane of length

1.	A block mass 3 kg slides down a frictionless inclined plane of length 6 m and height 4 m. if the block is released from rest at the top of the incline, what is its speed at the bottom?
Answer» 5m/s 6m/s 8m/s 9m/s Solution :FIRST, the kinetic energy the block gains is the same as the potential energyit LOSES, which is mgh, since this is equal to `(1)/(2)mv^(2)`, we find that `v=sqrt(2gh)`. PLUGGING in `g=10m//s^(2) and h=4m,` we GET `v=sqrt(30)~~9m//s`.

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A block mass 3 kg slides down a frictionless inclined plane of length 6 m and height 4 m. if the block is released from rest at the top of the incline, what is its speed at the bottom?

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