InterviewSolution
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InterviewSolution
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A block mass `m = 2 kg` is moving with velocity`v_(0)` towards a massless unstretched spring of the force constant `k = 10 N//m`. Coefficient of friction between the block and the ground is `mu = 0.2`. Find the maximum value of `v_(0)` so that after pressing the spring the block does not return back but stops there permanently. A. `2 sqrt((2)/(5)) m//s`B. `sqrt((1)/(5)) m//s`C. `4 sqrt((1)/(5)) m//s`D. `4 sqrt((2)/(5)) m//s` |
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Answer» Correct Answer - B Block will stop there if `kx = mu mg implies x = (mu mg)/(k)` ` implies x = (0.2 xx 2 xx 10)/(10) = (2)/(5) m` Now using energy conservation `(mv^(2))/(2) = (kx^(2))/(2) + mu mg (x+1) implies v = 4 sqrt((2)/(5)) m//s` |
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